if (historyRow[i]) Follow up: Did you use extra space? eval(ez_write_tag([[970,250],'tutorialcup_com-box-4','ezslot_4',622,'0','0'])); score = soldiersCount * rows + currentRowIndex. Github: code.dennyzhang.com Zero matrix is a matrix with all cells equal to 0. } } Here is my intuitive solution accepted by LeetCode judge : public class Solution { } for(int i = 0 ; i < numrows ; i++) { We can use the first column and the first row to track if a row/column should be set to 0. for (int k = 0; k < m; k++) the last lines are getting messed up in code-editor Here it is: for(int n : coord) To reduce the space required, we can use the matrix itself to store the flags for each row and column if they need to set to 0. } for (int j = 0; j < array.length; j++) { //set first row and column zero or not } This repository contains the solutions and explanations to the algorithm problems on LeetCode. The time complexity of the above code is O(n*logm+nlogn). List visitedRowIndex = new LinkedList(); The K Weakest Rows in a Matrix - Array - Easy - LeetCode. This problem should be solved in place, i.e., no other array should be used. really!!!!!! 4. } Given a 2D matrix, find the number non-empty sub matrices, such that the sum of the elements inside the sub matrix is equal to 0. for(int i=0; i

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tags. if(matrix[i][0] == 0 || matrix[0][j] == 0){ Minimum Number of Flips to Convert Binary Matrix to Zero - 刷题找工作 EP283 Given a m x n binary matrix mat. break; } So the rows arranged from weakest to strongest:2,0,3,1,4.eval(ez_write_tag([[300,250],'tutorialcup_com-medrectangle-4','ezslot_5',621,'0','0'])); To understand the approach better let us use the same example for better understanding. //set first column and row } for(int i = 0 ; i < numColumns ; i++) { } }, for(int column : columns) { Only medium or above are included. for(int x = 0; x < m[0].length; x++) } }. matrix[0][i] = 0; historyCol[j] = true; matrix[i][0] = 0; rows.add(i); Facebook: https://www.facebook.com/groups/2094071194216385/. matrix is filled with 0 or 1. while(k= m[0].length) for (int j = 0; j < array.length; j++) { { if(array[i][j] == 0) { System.out.println(" "); matrix[i][k] = 0; So to improve the time complexity we will use binary search to find the index of the first zero in each row and that index will be the number of ones in each row. } if (matrix[i][j] == 0) { [LeetCode] Set Matrix Zeroes (Java) July 24, 2014 by decoet. Size of each dimension, specified as a row vector of integer values. } for (int i = 0; i < n; i++) { else { row[i] = true; } Then iterate through the matrix if you find zero mark that row and column to zero in boolean matrix: At the end of first iteration we have marked all the rows or columns that should be marked to zero. for (int j = 0; j < array.length; j++) { i.e. boolean[] row = new boolean[matrix.length]; If it’s zero, for example, if matrix[i][j] is zero, we can update matrix[i][0] and matrix[0][j] to zero. Binary matrix is a matrix with all cells equal to 0 or 1 only. for(int i=0; i